Prove ASA congruence rule
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Angle-Side-Angle
Using words:
If two angle in one triangle are congruent to two angles of a second triangle,
and also if the included sides are congruent, then the triangles are congruent.
Using labels:
If in triangles ABC and DEF, angle A = angle D, angle B = angle E, and AB =
DE, then triangle ABC is congruent to triangle DEF.
Proof:
In the figure, the known congruent segments and angles in triangles ABC and
DEF are color-coded.
Construct a point F' on ray AC so that AF' = DF. Angle BAF' = angle BAC
and this = angle EDF and AB = DE (given), so triangle DEF = triangle ABF'.
There are two possibilities for point F': F' is the same as point C or
it is not.
If F' is not C, then F' is not on ray BC, since line AC and ray BC
only intersect at C. Thus the angle ABF' is not = angle ABC. But this
is a contradiction, since angle ABF' = angle DEF (because triangle DEF
= triangle ABF') and angle DEF = angle ABC (given). So this case cannot
occur.So it must be true that F' = C. Then triangle ABC = triangle ABF'
= triangle DEF.
QED
srevedabrundadevi:
SOURCE ; MATHS S FUN
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Answer:STATEMENT Two triangles are congruent if 2 angles and the included side of one triangle are equal to two triangles and the included side of other triangle.
Step-by-step explanation:See photo
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