prove by congruence property that the diagonals of a rhombus bisect each other at 90 degree.......
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Proof that the diagonals of a rhombus are perpendicular
Corresponding parts of congruent triangles are congruent, so all 4 angles (the ones in the middle) are congruent. This leads to the fact that they are all equal to 90 degrees, and the diagonals are perpendicular to each other.
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sorry bro the chaperone is in my syllabus but I have not read it yet so sorry
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