Question

Prove by contradiction that root 5 is not a rational number

Answer 1

Hey user !!

Here is your answer !!

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To prove ->√5 is irrational

Solution ->Let us suppose √5 is rational.

Now,

√5=p/q

squaring both sides

5=p^2/q^2

5q^2=p^2

P^2 is divisible by 5

Also p will be divisible by 5 Let p=5m put value of p

Now,

5=5m^2/q^2

5=25m^2/q^2

q^2=5m^2

q^2 is divisible by 5

Also q will be divisible by 5

5 is common factor

This shows our supposition was wrong.

√5 is an irrational number.

Hence proved !!

Hope it is satisfactory :-)
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Answer 2

Hello friend

Good afternoon

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Your answer is given in the attachment

I hope it will be satisfactory to u

Thanks

Have a great day