Prove, by direction
cosines, that the points (1,2,3), (4,0,4) and (-2,4,2) are collinear
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Answer:
Let P.V. of A = 1,2,3 =i+2j+3k
B= 4,0,4 =4i+0j+4k
C= -2,4,2 = -2i+4j+2k
P.V. of AB = (4i+0j+4k) - (i+2j+3k)
= 3i-2j+k
or p.v. of BC = (-2i+4j+2k) - (4i+0j+4k)
= -6i+4j-2k
or = -2(3i-2j+k)
p.v. of AB is equal to integral multiple of p.v. of BC . so given points are colliner
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