Prove by PMI that 2^5n>3^3n for all n€N
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prove
Step-by-step explanation:
2(5n)>3(3n)n=3,5*3=15,3*3=9
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2^5n>3^3n is true by PMI.
GIVEN: That all n belongs to the Natural Numbers.
TO PROVE:2^5n>3^3n
SOLUTION: As we know,
Case 1 : where n = 1
2⁵ⁿ > 3³ⁿ
when n = 1
2⁵ > 3³
25 > 9
Hence, the given statement is true for n = 1
Now let us assume that the statement is true for n =k as well.
Case 2: where n = a
2⁵ᵃ > 3³ᵃ -----Eq 1
Now, taking up n = k + 1,
2⁵⁽ᵃ⁺¹⁾ > 3³⁽ᵃ⁺¹⁾
Now, by using Eq 1,
2⁵ᵃ > 3³ᵃ
2⁵ᵃ. 2⁵ > 3³ᵃ . 2⁵
2⁵ᵃ⁺⁵ > 3³ᵃ. 2⁵
2⁵⁽ᵃ⁺¹⁾ > 3³ᵃ. 2⁵ > 3³ᵃ.3³ > 3³ᵃ⁺³ > 3³⁽ᵃ⁺¹⁾....
Hence the statement is true for n = k +a
Therefore, it can be said that
Using PMI, P(n) is true for all n belonging to Natural Numbers.
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