Question

Prove by Pythagoras' theorem that the diagonals of a rectangle are equal in length.​

Answer 1

Step-by-step explanation:

proof in pic...........

Answer 2

Answer:

For the asked question, we need to draw a rectangle, that is,

Consider a rectangle ABCD, Join B and D, similarly join A and C, therefore by joining this Diagonals AC and BD are formed.

Now in triangle BAD, BD

$\bold{= AB^2+AD^2( by \: pythagorus \: theorm.)}$

Similarly in triangleBAC

$\bold{AB=BC {}^{2} +AB {}^{2} (same \: reason.)}$

therefore BC=AD and AB is the commom in both,so AC

Which implies that AC =BD.

Which implies that AC =BD.Hence,Proved.