prove by the method of contradiction. If the bases and the heights of two triangles are equal, then the areas of the triangles are equal.
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Answer:
Step-by-step explanation:
Let me illustrate with an example of right angle triangles- ABC, with right angle at C, a and b are the sides forming the right angle and c is the hypotenuse.
a=1 b= 48 c =sq rt 2305 = 48.010 Area =24 sq cm
a=2 b= 24 c =sq rt 592 = 24.331 Area =24 sq cm
a=3 b= 16 c =sq rt 265 = 16.279 Area =24 sq cm
a=4 b= 12 c =sq rt 160 = 12.649 Area =24 sq cm
a=6 b= 8 c =sq rt 100 = 10 Area =24 sq cm
Though the areas of the 5 RATs are all the same they are not similar.
Conclusion: If 2 triangles have the same area, they are not similar.
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