Prove by the principle of mathemaatical induction3.6 + 6.9 + 9.12+.....+ 3n (3n + 3) = 3n(n + 1)(n + 2)
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3.6 + 6.9 + 9.12 + 3n *(3n+3) = 3n (n+1)(n+2)
1) let n = 1
then 3. 6 = 3*1 (1+1) (1+2) = 18 correct.
2) let the given expression be true for n = k.
Then for n = k+1,
3.6 + 6.9+9.12+....+ 3k (3k+3) + (3k+1) (3k+4)
= 3 k(k+1)(k+2) + (3k+3)(3k+6)
= 3( k+1) (k+2) [ k + 3]
This is in the form of 3 n (n+1)(n+2)
So that is proved by Induction.
1) let n = 1
then 3. 6 = 3*1 (1+1) (1+2) = 18 correct.
2) let the given expression be true for n = k.
Then for n = k+1,
3.6 + 6.9+9.12+....+ 3k (3k+3) + (3k+1) (3k+4)
= 3 k(k+1)(k+2) + (3k+3)(3k+6)
= 3( k+1) (k+2) [ k + 3]
This is in the form of 3 n (n+1)(n+2)
So that is proved by Induction.
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