Question

prove by two methods that sum of two odd numbers is even​

Answer 1

The sum of two odd integers is even. Proof: If m and n are odd integers then there exists integers a,b such that m = 2a+1 and n = 2b+1. m + n = 2a+1+2b+1 = 2(a+b+1).

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$answered \: by \: adi$

Answer 2

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Let the two odd numbers be, 2a+1 and 2b+1. So, 2a+1 + 2b+1 = 2(a+b)+2 = 2(a+b+1), which is even. Hence, proven.

➜ The sum of two odd integers is even. Proof: If m and n are odd integers then there exists integers a,b such that m = 2a+1 and n = 2b+1. m + n = 2a+1+2b+1 = 2(a+b+1).

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