Physics, asked by jallacharanreddy, 9 months ago

prove Carnot engine is most efficiency with diagram.....​

Answers

Answered by ibolbam
0

The Carnot Efficiency is the theoretical maximum efficiency one can get when the heat engine is operating between two temperatures: The temperature at which the high temperature reservoir operates ( THot ). The temperature at which the low temperature reservoir operates ( TCold ).

@Pravee14

Answered by Nicknwp
1

Answer:

The Carnot cycle is the most efficient engine possible based on the assumption of the absence of incidental wasteful processes such as friction, and the assumption of no conduction of heat between different parts of the engine at different temperatures. The efficiency of the carnot engine is defined as the ratio of the energy output to the energy input.

Explanation:

efficiency=net work done by heat engineheat absorbed by heat engine=−wsysqhigh(13.8.1)

=nRThighln(V2V1)+nRTlowln(V4V3)nRThighln(V2V1)(13.8.2)

Since processes II (2-3) and IV (4-1) are adiabatic,

(T2T3)CV/R=V3V2(13.8.3)

and

(T1T4)CV/R=V4V1(13.8.4)

And since T1 = T2 and T3 = T4,

V3V4=V2V1(13.8.5)

Therefore,

efficiency=nRThighln(V2V1)−nRTlowln(V2V1)nRThighln(V2V1)(13.8.6)

efficiency=Thigh−TlowThigh(13.8.7)

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