Question

prove:- Chapter name real no.s 10​

Answer 1

Answer:

which class this sums I don't know

Answer 2

Answer:

I can say only one

Step-by-step explanation:

Let us see √3

now,

assume √3 is rational

√3=p/q. ( p,q)=1

squaring on both sides,

(√3)2=(p/q)2

3=p2/q2

q2=p2/3. -eq1

p2 is divisible by 3

p is divisible by 3

p=3r

substitute p=3r in eq1

q2=(3r)2/3:

q2=(3r)2

q2/3 =r2

q2 is divisible by 3

q is divisible by 3

p& q are divisible by 3

HCF of ( p,q) =3

for a rational number HCF must be 1 but, here HCF is 3

by the contradiction,

√3 is not a rational

it is a irrational

hence, we proove √3 is a irrational