Question

prove converse mid point theorem
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Answer 1

Step-by-step explanation:

prove converse mid point theorem

is the mid-point of AC.

∴DE

1

∣∣BC (Mid-point theorem parallels)

But DE∣∣BC (Given)

This is possible only if E and E d

1

consider (Through a given point, only one line can be drawn ∣∣ to be a given line)

herefore, E and E

1

coincide.

ie. DE

1

is the same as DE.

Thus a line drawn through the mid-point of a side of a triangle and parallel to another bisects the thirdside.

Hence, E=E

1

and E is the mid-point of AC