Question

Prove: cos (
π
2
+ θ) ∙ sec(−θ) ∙ tan(π − θ) + sec(2π + θ) ∙ sin(π + θ) ∙ cot (
π
2
− θ) = 0

Answer 1

Answer:

cos(2π−θ).sin(π+θ).tan(2π−θ)cot(2π+θ)).sin(−θ).(cotπ−θ)=−cosecθ

(cosθ)(−sinθ)(−tanθ)(−tanθ)(−sinθ)(−cotθ)=−cosecθ

cosθcotθ=cosecθ

cosθ1×sinθcosθ=sinθ1

1=1