CBSE BOARD X, asked by inst54, 1 year ago

Prove cos(90°-x) = sin x.

Answers

Answered by Anonymous
10

To prove cos(90°-x) = sin x.

By using identity of cos(A-B),

= cosA.cosB + sinA.sinB

= cos90°. cos x + sin90°. sinx

= 0.cos x + 1(sinx)

= sin x.

Answered by brainlystargirl
2

Heya ____

Que __ Prove cos(90°-x) = sin x.

Solution ____

cos(90°-x) = sin x.

Prove by the identity Cos ( A- B )

__

______

cos A. cos B + sin A . sin B

cos 90° . cos x + sin 90° . sin x

0.cos x + 1 ( Sin x )

cos ( 90°-x) = sin x ...

Thank you

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