Math, asked by yash129910, 4 months ago

prove
cos²Θ+tan²Θ/sin²Θ -1 = tan²Θ

Answers

Answered by Anonymous

3

sin²θcosec(90°-θ) - cot²(90°-θ)cosθ = sin²θ/cosθ - tan²θ cosθ = sin²θ/cosθ - sin²θ/cosθ cos²θ

= sin²θ/cosθ - sin²θ/cosθ = 0

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