Math, asked by AR19Z, 3 months ago

Prove cos² x/1+sin x =1-sin x
Please reply as soon as possible​

Answers

Answered by antraanand100
0

Answer:

10

Step-by-step explanation:

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Answered by sakshi200736
1

Answer:

sin x - cos x +1)/ (sin x + cos x -1) = 1 / (sec x - tan x )

Step-by-step explanation:

LHS = ( sin x - cos x +1)/ (sin x + cos x -1)

Multiplying & Dividing by (sin x + cos x + 1)

= {(Sin x+ 1)² - Cos²x } / { (sin x + cos x)² - 1² }

= (Sin²x + 1 + 2Sinx - Cos²x) / (sin²x + cos²x + 2SinxCosx - 1)

using sin²x + cos²x = 1 or 1 - cos²x = Sin²x

= (Sin²x + 2Sinx + Sin²x) / (1 + 2SinxCosx - 1)

= (2Sin²x + 2Sinx) /(2SinxCosx)

= (Sinx + 1) /Cosx

Multiplying & Dividing by 1 - Sinx

= (1 - Sin²x) /(Cosx (1 - Sinx))

= Cos²x/(Cosx (1 - Sinx))

= Cosx/(1 - Sinx)

= 1/(1/Cosx - Sinx/Cosx)

= 1/(Secx - tanx)

= RHS

QED

Proved

answer = ( sin x - cos x +1)/ (sin x + cos x -1) = 1 / (sec x -tan x)

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