prove cos²ø-sin²ø=tan²ø
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Step-by-step explanation:
We have , LHS =cos ²theta(1+tan²theta)
=cos²theta (1+tan²theta)
= cos²theta.1+tan²theta.cos²theta
= cos²theta +sin²theta /cos²theta.cos²theta
= sin²theta +cos²theta
= 1
Hence proved
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