Question

prove cosec(67+theta)-sec(23-theta)=0
plzz help me​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Hey there!

L.H.S:

cosec (67 + Ф) - sec (23 - Ф)

= sec { 90 - (67 + Ф)} - sec(23 - Ф)

= sec (23 - Ф) - sec (23 - Ф)

= 0

= R.H.S