prove cot(15/2)=√2+√3 +√4 +√6
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Best Answer: cot(15/2)°
= cos(15/2)° / sin(15/2)°
= 2cos^2 (15/2)° / 2sin(15/2)° cos(15/2)°
= (1 + cos15°)/sin15°
Plugging cos15° = (1/4) (√6 + √2) and sin15° = (1/4) (√6 - √2)
= [1 + (1/4) (√6 + √2)] / [(1/4) (√6 - √2)]
Answer By Ayush...
= cos(15/2)° / sin(15/2)°
= 2cos^2 (15/2)° / 2sin(15/2)° cos(15/2)°
= (1 + cos15°)/sin15°
Plugging cos15° = (1/4) (√6 + √2) and sin15° = (1/4) (√6 - √2)
= [1 + (1/4) (√6 + √2)] / [(1/4) (√6 - √2)]
Answer By Ayush...
Answered by
36
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