prove cotA + cosecA - 1 / cotA - cosecA + 1 = cosecA + cotA
Answers
refer to the attachment

Step-by-step explanation:
To prove,
(cot A + cosec A -1) = (1+cos A)
(cot A - cosec A +1) sin A
LHS= cos A + 1 - sin A
sin A sin A sin A
cos A - 1 + sin A
sin A sin A sin A
= (cos A + 1 - sin A) × (cos A + 1 - sin A)
(cos A - 1 + sin A) (cos A + 1 - sin A)
= (cos A + 1 - sin A) (cos A + 1 - sin A)
(cos A - 1 + sin A) (cos A + 1 - sin A)
= (cos A + 1 - sin A)^2
cos^2 A - (1 - sin A)^2
= (cos^2 A - 2 cos A (1 - sin A) + (1 - sin A)^2)
(cos^2 A - 1 + 2 sin A - sin^2 A)
= cos^2 A-2cosA+2 sinA cosA +1-2 sinA + sin^2 A
1 - sin^2 A - 1 + 2 sin A - sin^2 A
= (2 - 2 cos A + 2 sin A cos A - 2 sin A)
(2 sin A - 2 sin^2 A)
= 2 (1 - cos A) (1 - sin A)
(2 sin A (1 - sin A) )
= 1 - cos A
sin A
= RHS