Question

Prove divisibility test of 2ⁿ. (The most logical one gets points, otherwise reported.)

Answer 1

Divisibility test of 4

100÷4=25 therefore 4 divides 100. So the digit of 100 is always divisible by 100.

Any digit above the digit of 100 is divisible by 100.

This means we can check below the digit of 100.

Divisibility test of 8

1000÷8=125 therefore 8 divides 1000. Like the previous one, it can be proven by checking below the digit of 1000.

And so on...

Divisibility test of 2ⁿ

2ⁿ×5ⁿ=10ⁿ, so 2ⁿ divides 10ⁿ. If we check the digit below the digit of 10ⁿ, the divisibility test is over.

∴In the divisibility test of 2ⁿ, we can check below the digit of 10ⁿ.

Answer 2

Answer:

i hope this is the answer you are looking for

Divisibility by 2: The number should have 0 , 2 , 4 , 6 , 0, \ 2, \ 4, \ 6, 0, 2, 4, 6, or 8 8 8 as the units digit. Divisibility by 3: The sum of digits of the number must be divisible by 3 3 3. Divisibility by 4: The number formed by the tens and units digit of the number must be divisible by 4 4 4.

Step-by-step explanation: