Physics, asked by shivam5588, 1 year ago

Prove E = MC^2 in short form

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Answered by Aman85428
2
In physical theories prior to that of special relativity, mass and energy were viewed as distinct entities. Furthermore, the energy of a body at rest could be assigned an arbitrary value. In special relativity, however, the energy of a body at rest is determined to be mc2. Thus, each body of rest mass m possesses mc2of “rest energy,” which potentially is available for conversion to other forms of energy. The mass-energy relation, moreover, implies that, if energy is released from the body as a result of such a conversion, then the rest mass of the body will decrease. Such a conversion of rest energy to other forms of energy occurs in ordinary chemical reactions, but much larger conversions occur in nuclear reactions. This is particularly true in the case of nuclear fusionreactions that transform hydrogen to helium, in which 0.7 percent of the original rest energy of the hydrogen is converted to other forms of energy. Stars like the Sun shine from the energy released from the rest energy of hydrogen atoms that are fused to form helium.
Answered by fanbruhh
0
 \huge \bf{ \red{hey}}

 \huge{ \mathfrak{here \: is \: answer}}

pls see in pic

in this famous equation

e is energy

m is mass

and c ^2 is speed of light

using this equation

Einstein showed the relationship between the mass and energy.

and according to the theory of relativity

nothing can travel higher than the speed of light.

which values 299729458m/s

 \huge \boxed{ \boxed{ \green{hope \: it \: helps}}}

 \huge{ \pink{thanks}}
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