Question

prove e=mc^2
plz. help me to prove

Answer 1

Let M = mass
       E = energy
       C = speed of light in vacuum
M2 X C2 = (Ml2 + Mw2 +Mmh2)
Adding 4th term energy
M2 X C2 = (Ml2 +Mw2 + MH2) + E2
Normalizing energy by dividing C2
M2 X c2 = (Ml2 + Mw2 + MH2) + E2/C2
At rest momentum is zero
M2 X C2 = 0 + E2/C2
M2 X C2 = E2/C2
M2 X C2 X C2= E2
E2 = M2 X C4
Taking root of the whole equation
√ (E2 = M2 X C4)
E = MC2

Answer 2

$\huge \bf{ \red{hey}}$

$\huge{ \mathfrak{here \: is \: answer}}$

pls see in pic

in this famous equation

e is energy

m is mass

and c ^2 is speed of light

using this equation

Einstein showed the relationship between the mass and energy.

and according to the theory of relativity

nothing can travel higher than the speed of light.

which values 299729458m/s

$\huge \boxed{ \boxed{ \green{hope \: it \: helps}}}$

$\huge{ \pink{thanks}}$