Question

PROVE E=mc^2$<svg height="150" width="400">\ \textless \ br /\ \textgreater \ <defs>\ \textless \ br /\ \textgreater \ <linearGradient id="grad1" x1="0%" y1="0%" x2="100%" y2="0%">\ \textless \ br /\ \textgreater \ <stop offset="0%" style="stop-color:rgb(255,255,0);stop-opacity:1" />\ \textless \ br /\ \textgreater \ <stop offset="100%" style="stop-color:rgb(255,0,0);stop-opacity:1" />\ \textless \ br /\ \textgreater \ </linearGradient>\ \textless \ br /\ \textgreater \ </defs>\ \textless \ br /\ \textgreater \ <ellipse cx="200" cy="70" rx="85" ry="55" fill="url(#grad1)" />\ \textless \ br /\ \textgreater \ </svg>$​

Answer 1

kanda=h/p

p=h/lameda-------------(1

E=hC/lamda-----------(2

putting value of p in ------(2

E=pc

if we don't assume velocity is equal to speed of light

E=mc^2

Answer 2

E = relativistic kinetic energy + mc^2

0+mc^2

mc^2

so :

E = mc^2

hope it helps

mark as BRAINLIEST answer!!