Prove. Equal chords of a corlce subtended equal angles at the centre
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Step-by-step explanation:
Answer
In ΔAOB and ΔCOD,
AB=CD (Given)
AO=CO (radius)
OB=OD (radius)
By S.S.S congruency, ΔAOB≅ΔCOD
⇒∠AOB=∠COD.
Answered by
3
Answer:
Given: AB and CD are equal chords of
the same circle with centres or O
To prove: angle AOB = angle COD
proof: In Triangle AOB and Triangle COD
AO= CO (radii of the same circle)
AB = CD (given)
OB = OC (radii of the same circle)
Therefore Triangle AOB is congruent
to Triangle COD by SA Congruence rule...
The implies and angle AOB is equal to angle
COD...
hence proved.
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