prove exterior angle property af triangle
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Step-by-step explanation:
तुम्हें मैं 1 दिन के अंदर इस सवाल का जवाब बता दूंगा फुल प्रूफ
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Statement:-
An exterior angle of a triangle is equal to the sum of its interior opposite angles.
Consider triangle ABC.
∠ACD is an exterior angle.
Through C, draw
CE//BA
To prove:
∠ 1 + ∠2 = ∠ACD
Proof:
∠1 = ∠x (pair of alternate interior angles since, CE||BA)
∠2 = ∠y (pair of corresponding angles)
∠1 + ∠2 =∠x + ∠y
i.e.
∠1 + ∠2 = ∠ACD [∵∠x + ∠y = ∠ACD]
Hence proved.
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