prove f=m a
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Now According to Newton’s 2nd Law of Motion:
F α dp/dt
F = k dp/dt
F = k d(mv)/dt
F = k md(v)/dt
F = k ma
Experimentally k =1
F = k ma
Which is the required equation of force.
• may it helps u.....
F α dp/dt
F = k dp/dt
F = k d(mv)/dt
F = k md(v)/dt
F = k ma
Experimentally k =1
F = k ma
Which is the required equation of force.
• may it helps u.....
Answered by
0
initial momentum= mu
final momentum=mv
change in momentum=mv-mu
rate of change in momentum=mv-mu/t
according to second law of motion
F <mv-mu/t (<= DIRECTLY PROPORTIONAL)
F <m (v-u)/t
F <ma
F=kma (k=constant)
F=ma
PLZ MARK IT BRAINLIST.......
final momentum=mv
change in momentum=mv-mu
rate of change in momentum=mv-mu/t
according to second law of motion
F <mv-mu/t (<= DIRECTLY PROPORTIONAL)
F <m (v-u)/t
F <ma
F=kma (k=constant)
F=ma
PLZ MARK IT BRAINLIST.......
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