Prove f:R —> R, f (x) = 2ˣ+2⁻ˣ is increasing for x ∈ (0, ∞) and decreasing for x ∈ (-∞, 0)
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we have to prove , f(x) = 2ˣ+2⁻ˣ is increasing for x ∈ ( 0, ∞) and decreasing for x ∈ ( -∞, 0)
concept : any function , y = f(x) is decreasing on (a, b) only if f'(x) < 0 and increasing only if f'(x) > 0 on (a, b).
so, first of all, differentiate f(x) with respect to x,
f'(x) = 2ˣln2 -2⁻ˣln2 = ln2(2ˣ - 2⁻ˣ)
putting, f'(x) = ln2(2ˣ - 2⁻ˣ) = 0
⇒2ˣ = 2⁻ˣ
⇒ x = 0
case 1 : when x > 0
⇒ 2ˣ > 2⁻ˣ
⇒2ˣ - 2⁻ˣ > 0
⇒ln2(2ˣ - 2⁻ˣ) > 0 ⇒f'(x) > 0
hence, f(x) is increasing for x ∈ (0, ∞)
case 2 : when x < 0
⇒2ˣ < 2⁻ˣ
⇒2ˣ - 2⁻ˣ < 0
⇒ln2(2ˣ - 2⁻ˣ) < 0 ⇒f'(x) < 0
hence, f(x) is decreasing for x ∈ (-∞, 0)
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