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Answer 1

LHS = ( 1 + tan²θ ) ( 1 + sinθ ) ( 1 - sinθ )

= ( sec²θ ) ( 1 - sin²θ )

= ( sec²θ ) ( cos²θ )

= ( sec²θ ) ( 1/sec²θ )

= 1

= RHS

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Answer 2

Answer:

• (1+tan2θ)(1+sinθ)(1-sinθ)
• =(sec2θ)(1−sin2θ)
• =(sec2θ)(cos2θ)
• =(sec2θ)(sec2θ1)
• =1