Prove for S. H. M. a=-w²x
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If the total force F on a mass m follows Hooke's law,
F = −kx,
then one can use Newton's 2nd law
F=ma,
to infer that the motion is a simple harmonic motion
a=−ω2(square)x,
2π/T = ω =(square root)-/k/m ,
cf. OP's correct belief. Now it only remains to solve the ODE
d2(square)x(t)/dt2(square) = −ω2(square)x(t),
Explanation:
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