Prove Force = Mass × Acceleration
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Answered by
51
F = Mass X Acceleration
Where F directly proportional to rate of change of momentum
F is proportional to (v-u) / t
If we are removing the proportional then there would be a constant added lets assume the constant as K
F=k(v-u/t)
k is constant so k=1
momentum=mv
f=k(-u/t)mv
f=mk(v-u/t) since v-u/t =a
f=kma where k is constant
f=ma
Where F directly proportional to rate of change of momentum
F is proportional to (v-u) / t
If we are removing the proportional then there would be a constant added lets assume the constant as K
F=k(v-u/t)
k is constant so k=1
momentum=mv
f=k(-u/t)mv
f=mk(v-u/t) since v-u/t =a
f=kma where k is constant
f=ma
Answered by
18
by newtons 2nd law of motion,
momentum is directly proportional to F
hence dp/dt proportional to F
F=k(dp/dt)
in si unit k=1
F=dp/dt=d(mv)/dt
since m is const.
Hence F=ma
momentum is directly proportional to F
hence dp/dt proportional to F
F=k(dp/dt)
in si unit k=1
F=dp/dt=d(mv)/dt
since m is const.
Hence F=ma
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