Physics, asked by amarjeet7061kr, 10 months ago

prove Gauss theorem​

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Answered by rajikoshy
6

Answer:Gauss theorem states that the electric flux ΦE through any closed surface is equal to 1 / ɛo times the 'net' charge q is enclosed by the surface .

Proof :-

Let q be the charge .

Let us construct the Gaussian sphere of radius r .

Consider , A surface or area ds having having ds(vector) .

Normal having the flux at ds .

Flux at ds .

d e = E (vector) d s (vector) cos θ

But , θ = 0 .

Total flux

C = f d Φ

E 4 π r^2

σ = 1 / 4πɛo q / r^2 × 4π r^2

σ = q / ɛo (proved)

Explanation:

Answered by acsahjosemon40
3

Answer:Gauss theorem states that the electric flux ΦE through any closed surface is equal to 1 / ɛo times the 'net' charge q is enclosed by the surface .

Proof :-

Let q be the charge .

Let us construct the Gaussian sphere of radius r .

Consider , A surface or area ds having having ds(vector) .

Normal having the flux at ds .

Flux at ds .

d e = E (vector) d s (vector) cos θ

But , θ = 0 .

Total flux

C = f d Φ

E 4 π r^2

σ = 1 / 4πɛo q / r^2 × 4π r^2

σ = q / ɛo (proved)

Explanation:

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