prove Gauss theorem
Answers
Answer:Gauss theorem states that the electric flux ΦE through any closed surface is equal to 1 / ɛo times the 'net' charge q is enclosed by the surface .
Proof :-
Let q be the charge .
Let us construct the Gaussian sphere of radius r .
Consider , A surface or area ds having having ds(vector) .
Normal having the flux at ds .
Flux at ds .
d e = E (vector) d s (vector) cos θ
But , θ = 0 .
Total flux
C = f d Φ
E 4 π r^2
σ = 1 / 4πɛo q / r^2 × 4π r^2
σ = q / ɛo (proved)
Explanation:
Answer:Gauss theorem states that the electric flux ΦE through any closed surface is equal to 1 / ɛo times the 'net' charge q is enclosed by the surface .
Proof :-
Let q be the charge .
Let us construct the Gaussian sphere of radius r .
Consider , A surface or area ds having having ds(vector) .
Normal having the flux at ds .
Flux at ds .
d e = E (vector) d s (vector) cos θ
But , θ = 0 .
Total flux
C = f d Φ
E 4 π r^2
σ = 1 / 4πɛo q / r^2 × 4π r^2
σ = q / ɛo (proved)
Explanation: