Question

prove geometrically : tan(180-A) = -tanA ​

Answer 1

Step-by-step explanation:

1. we use the fomula :tan(A-B)=
2. $\frac{tana - tanb}{1 + tana \: tanb}$
3. tan(180-a)=
4. $\frac{tan180 - tana}{1 + tan180.tana}$
5. but,tan 180=0 hence,we get