Question

prove geometrically the value of sin 60

Answer 1

Hii dear here is your answer hope it helps you!!

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Answer 2

let's consider an equilateral traiangle with each side 2a and each angle equal to 60°
draw AD perpendicular to BC
then ,
Triangle ABD is congruent to triangleACD
BD =CD = a
also anlge BAD=angleCAD =30°

AD = √AB square -BD square = (√ 2a)square -a square = root 3a

sin 60° = AD/AB= root 3a /2a = √ 3 / 2