Question

Prove given laws of Boolean Algebra:
1)A+A+A=A
2)A.A.A=A
3)A+B=B+A
4)A.B=B.A
5)A+(B+C)=C+(A+B)
6)A.(B.C)=C.(A.B)
7)A(B+C)=A.B+A.C
8)(A+B)(A+C)=A+BC
9)A+0=A
10)A.0=0
11)A+1=1
12)A.1=A
13)A+A bar =1
14)A.A bar=1
15)A bar bar=A
Pls provide me solutions in notebook or in this pls I need a big help I will mark u as brainliest pls provide me solutions.​​

Answer 1

Answer:

i dont still get algebra...it os tough