prove hee following
as irrahimae
3+√2
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Step-by-step explanation:
To Prove :- 3√2 is irrational number.
⚫ Proof :- Let 3√2 = p/q is rational number.
\begin{lgathered}3 \sqrt{2} = \frac{p}{q} \\ \\ \sqrt{2} = \frac{p}{3q} \\ \\\end{lgathered}
3
2
=
q
p
2
=
3q
p
√2 is an irrational number ..
irrational no. ≠ Rational no.
Hence, our supposition is wrong.
Therefore 3√2 is an irrational no
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