prove highest value of sin theeta is 1
Answers
Answered by
2
Answer:
Maximum value of sin θ is 1 when θ = 90 ˚. Minimum value of sin θ is –1 when θ = 270 ˚. So, the range of values of sin θ is –1 ≤ sin θ ≤ 1. As the point θ moves round the unit circle in either the clockwise or anticlockwise direction, the sine curve above repeats itself for every interval of 360˚.
Answered by
22
Answer:
Maximum value of sin θ is 1 when θ = 90 ˚. Minimum value of sin θ is –1 when θ = 270 ˚. So, the range of values of sin θ is –1 ≤ sin θ ≤ 1. As the point θ moves round the unit circle in either the clockwise or anticlockwise direction, the sine curve above repeats itself for every interval of 360˚.
Similar questions