prove if a triangle and a parallelogram are on 5he same base and between same parallels the area of 5he triangle is equal to half of the parallelogram
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Step-by-step explanation:
a r b. c
d e
(that's the diagram u need. join them)
given:- parallelgram abed and and ∆dce with the same base de and between two // line AC and de.
construction: d is produced to r such that drce is a parallelgram.
proof:- ar. of the parallelogram abed = ar of the parallelgram drce ---------1
( see theorem:- it says two parallelgram will be equal if they have same base and are between to parallel lines)
also, (ar. means area)
ar. of ∆dce= 1/2 of ar. of parallelogram drce ---- 2
( since diagonal bisects the parallelgram into two equal traingles.
then from 1 and 2 we have
ar. of ∆dce= 1/2 of ar. of parallelogram abed
hope this help
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