Question

Prove, if the diagonals of a cyclic qui
perpendicular to each other, she
a wide is perpendicular to the opposite​

Answer 1

Answer:

if, the diagonals of a cyclic quadrilateral are perpendicular to each other,

show that the line passing through the point of interaction of the diagonals and the midpoint of a side, is perpendicular to the opposite side

Let T be the given midpoint of PQ,

Now in a circle line joining the midpoint of chord and center is perpendicular to the chord

so angle PTO is 90 degree

if we take triangles PTO and QYO, we can prove them congruent by SAS

so angle TPO and angle TQO are congruent by C.P.C.T.

similarly angle POT and QOT

so 

angle POT + angle QOT = 90.....given that diagonals are perpendicular

angle POT = angle QOT = 45

in triangle PTO

angle POT = 45

angle PTO = 90

so

angle TPO = 45

hence 

angle TPO = angle TQO = 45

now

angle OSU= angle TPO = 45... angles subtended by same arc

angle TQO = angle ORU = 45... angles subtended by same arc

angle TOQ = angle SOU = 45... vertically opp. angles

angle POT = angle ROU = 45... vertically opp. angles 

now in triangle OSU

angle OSU= 45

angle SOU = 45

hence

angle OUS = 90...sum of all angles in triangle

hence proved

 

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Step-by-step explanation: