Question

Prove if triangle ABC is an isosceles triangle such that AB is equal to AC, then altitude AD from A on BC bisects BC

Answer 1

Given,
In the isosceles triangle ABC,
AB=AC
AD is an altitude

To prove: BD=CD

Proof:
In ∆ABD and ∆ACD,
AB=AC (given)
AD=AD (common)
<ADB=<ADC (90° each, since, AD is an altitude)

therefore, ∆ABD=~∆ACD (RHS)
=>BD=CD (CPCT)

HENCE PROVED

Answer 2

CRM

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