prove if x and y are two odd positive integer then x²+y² is even but not devisible by 4
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let x=2m+1
y=2n+1
x²+y²=(2m+1)²+(2n+1)²
⇒4m²+1+4m+4n²+1+4n
⇒all terms are even so it is even
taking 4 common
4(m²+m+n²+n)+2
here while dividing by 4 we get 2 as remainder hence not divisible
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