Question

prove iiiiiiiiiiittttttttttt


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Answer 1

Step-by-step explanation:

LHS => cot A + cosec A - 1/cot A - cosec A + 1

=> cot A + cosec A - (cosec²A - cot²A)/(cot A-cosec A + 1)

[ 1 + cot²A = cosec²A => 1 = cosec²A - cot²A ]

=> cot A + cosec A - [ (cosec A+cot A)(cosec A-cotA) ]/ (cot A - cosec A + 1)

[ a² - b² = (a+b)(a-b) ]

=> (cot A + cosec A)(1 - cosec A + cot A)/cotA - cosec A + 1)

=> cot A + cosec A

[ 1-cosec A + cot A cancels out ]

=> cos A/sin A + 1/sin A

=> (cos A + 1) / sin A

hence proved

Answer 2

see the above soln mark as brainliest soln

sorry for late soln i copied qn wrng