prove iiiiiiiiiiittttttttttt
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Step-by-step explanation:
LHS => cot A + cosec A - 1/cot A - cosec A + 1
=> cot A + cosec A - (cosec²A - cot²A)/(cot A-cosec A + 1)
[ 1 + cot²A = cosec²A => 1 = cosec²A - cot²A ]
=> cot A + cosec A - [ (cosec A+cot A)(cosec A-cotA) ]/ (cot A - cosec A + 1)
[ a² - b² = (a+b)(a-b) ]
=> (cot A + cosec A)(1 - cosec A + cot A)/cotA - cosec A + 1)
=> cot A + cosec A
[ 1-cosec A + cot A cancels out ]
=> cos A/sin A + 1/sin A
=> (cos A + 1) / sin A
hence proved
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see the above soln mark as brainliest soln
sorry for late soln i copied qn wrng
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