Prove inductive and deductive that the sum of six consecutive integers is a multiple of 3?
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3+3+3+3+3+3=18....... 18÷3=6
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4+6+8+10+12+14=54
according to divisibility test of 3: 5 + 4 is equal to 9 ,9 is a multiple of 3 as well as it is divisible by 3. prove that the sum of six consecutive integers is divisible by 3 that is it is the multiple of 3 AS 54 is the sum of 6 consecutive integers and it is also divisible by 3 so it prove that the sum of any two consecutive integers is divisible by 3. HOPE HELPFUL FOR U BUDDY....... follow me please ....!!!!!
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