Question

prove ir
:-√3 cosec 20-sec20=4

Answer 1

Helo... ☺



please refer to the attachment above

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Answer 2

$LHS= \: \sqrt{3} cosec \: 20 - sec \: 20 \\\\ = \frac{ \sqrt{3} }{sin20} - \frac{1}{cos20} \\ \\= \frac{2( \frac{ \sqrt{3} }{2} \: cos20 - \frac{1}{2} \: sin \: 20)}{sin20 \: cos20}$

$= \frac{2( sin60 \: cos20 - cos60 \: sin \: 20)}{sin20 \: cos20} \\\\ = \frac{2sin(60 - 20)}{sin20 \: cos20}$

$= \frac{4 \: sin40}{2sin20 \: cos20} \\\\ = \frac{4 \: sin40}{sin40}\\ \\ = 4 = RHS$