Question

PROVE IT..................​

Answer 1

hope this helps you☺️☺️

Answer 2

Answer:

I hope you understand

Step-by-step explanation:

Let theta = A

1/cosA+sinA-1 +1/cosA+sinA+1

Using identity (a+b)(a-b)=(a^2-b^2)

=cosA+sinA+1-1+cosA+sinA/ (cosA+sinA)^2-(1)^2

=2(cosA+sinA)/cos^2A+sin^2A-1+ 2cosAsinA

Using identity, cos^2A+sin^2A=1.

=2(cosA+sinA)/1-1+2sinAcosA

=2(cosA +sinA)/2sinAcosA

=cosA+sinA/sinAcosA

= cos/sinAcosA + sinA/sinAcosA

= 1/sinA + 1/cosA

= cosecA + secA

Hence proved...........