prove it..
...............................
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Step-by-step explanation:
1/tan3A-tanA-1/cot3A-cotA
=1/(sin3A/cos3A)-(sinA/cosA) -1/(cos3A/sin3A)-(cosA/sinA)
=cosAcos3A/sin3AcosA-cos3AcosA -sinAsin3A/cos3AsinA-cosAsin3A
=cosAcos3A/sin(3A-A)-sinAsin3A/sin(A-2A)
=cosAcos3A/sin2A+sinAsin3A/sin2A
=cosAcos3A+sinAsin3A/sin2A
=cos(A-3A)/sin2A
=cos2A/sin2A
=cot2A
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Answer:
Step-by-step explanation:mark me if you can i needed
The answer is here,
Given that,
= > \: \frac{a + ib}{c + id} = p + iq
We can replace the " i " as " -i ".
= > \frac{a - ib}{c - id} = p - iq
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