Question

Prove it.... ........ ....​

Answer 1

Answer:

................................... Mark as brainlist..........................

Answer 2

Answer:

L.H.S=R.H.S

Step-by-step explanation:

$2a^{2}$+$2b^{2}$+$2c^{2}$-2ab-2bc-2ca=[$(a-b)^{2}$+$(b-c)^{2}$+$(a-c)^{2}$]

L.H.S:-

($a^{2}$+$a^{2}$)+($b^{2}$+ $b^{2}$)+($c^{2}$+$c^{2}$)-2ab-2bc-2ca

($a^{2}$+$b^{2}$-2ab)+($b^{2}$+$c^{2}$-2bc)+($a^{2}$+$c^{2}$-2ca)      

from the formula {$(a-b)^{2}$=($a^{2}$+$b^{2}$-2ab)} we can write the above equation as

$(a-b)^{2}$+$(b-c)^{2}$+$(a-c)^{2}$