Prove it.................
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3
Answer:
Answer:
{e}^{x} - 2 = 0e
x
−2=0
{e}^{x} = 2e
x
=2
ln( {e}^{x} ) = ln(2)ln(e
x
)=ln(2)
x.ln(e) = ln(2)x.ln(e)=ln(2)
x.1 = ln(2)x.1=ln(2)
x = ln(2)x=ln(2)
x = 0.6932x=0.6932
Hopes it helps
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9
- By this e^x -2=0 has a solution between 0 and 1
- This is the correct answer for your question .
- Solved by S.Haries Ram
- Hopes it helps you.
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- Thank and mark brainliest for my work.
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