Question

Prove it...

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Answer 1

We have,

We have,According to given figure.

We have,According to given figure.PQ=PR(giventhat)

We have,According to given figure.PQ=PR(giventhat)QS=SR(Bydefinationofmidpoint)

We have,According to given figure.PQ=PR(giventhat)QS=SR(Bydefinationofmidpoint)PS=PS(Commonline)

We have,According to given figure.PQ=PR(giventhat)QS=SR(Bydefinationofmidpoint)PS=PS(Commonline)Then,

We have,According to given figure.PQ=PR(giventhat)QS=SR(Bydefinationofmidpoint)PS=PS(Commonline)Then,ΔSPQ≅ΔSPR (BY congruency S.S.S.)

We have,According to given figure.PQ=PR(giventhat)QS=SR(Bydefinationofmidpoint)PS=PS(Commonline)Then,ΔSPQ≅ΔSPR (BY congruency S.S.S.)Hence, PS bisects ∠PQR by definition of angle bisector.

Answer 2

Answer:

In triangle PSQ and PSR

angle PSQ = angle PSR. ( PS is perpendicular to QR

PQ=PR. (given)

PS = PS. (common)

So by RHS congurency rule triangle PSQ congurent to triangle PSR

Angle Q = Angle R. (by C.P.C.T)