Math, asked by sauravrnps, 1 year ago

prove it..................

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Answered by sahuraj457
1

7 log( \frac{16}{15} )  + 5 log( \frac{25}{24} )  + 3 log( \frac{81}{80} )  \\  =  log( { (\frac{16}{15}) }^{7} )  +  log( {( \frac{25}{24}) }^{5} )  +  log( { (\frac{81}{80}) }^{3} )  \\  =  log( \frac{ {16}^{7} \times  {25}^{5}  \times  {81}^{3}  }{ {15}^{7}  \times  {24}^{5}  \times  {80}^{3} } )  \\  =  log(2)
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Answered by sanjeevravish321
0

Answer:mark me if you can

Step-by-step explanation:

The answer is here,

Given that,

= > \: \frac{a + ib}{c + id} = p + iq

We can replace the " i " as " -i ".

= > \frac{a - ib}{c - id} = p - iq

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