Question

prove it..................

Answer 1

$7 log( \frac{16}{15} ) + 5 log( \frac{25}{24} ) + 3 log( \frac{81}{80} ) \\ = log( { (\frac{16}{15}) }^{7} ) + log( {( \frac{25}{24}) }^{5} ) + log( { (\frac{81}{80}) }^{3} ) \\ = log( \frac{ {16}^{7} \times {25}^{5} \times {81}^{3} }{ {15}^{7} \times {24}^{5} \times {80}^{3} } ) \\ = log(2)$
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Answer 2

Answer:mark me if you can

Step-by-step explanation:

The answer is here,

Given that,

= > \: \frac{a + ib}{c + id} = p + iq

We can replace the " i " as " -i ".

= > \frac{a - ib}{c - id} = p - iq